中南大學(xué)物化課后習(xí)題答案9章可逆原電池

1、第9章可逆原電池可逆原電池1寫(xiě)出下列原電池中各電極反應(yīng)、電池反應(yīng)及E的計(jì)算公式。①②PtH2(101325Pa)｜KOH(a)｜O2(101325Pa)Pt③④解：(1)負(fù)極Pb(s)(a)→PbSO4(s)2e正極Cu2()2e→Cu(s)電池反應(yīng)Pb(s)SO4(a)Cu2(aCu2)====PbSO4(s)Cu(s)(2)負(fù)極H2(pΘ)2e→2H(aH)正極?O2(pΘ)H2O2e→2OH(aOH)電池反應(yīng)H2(pΘ)?O

2、2(pΘ)→H2O(l)(3)負(fù)極3H2(pH2)6e→6H(aq)(2)負(fù)極Ni(s)2OH→NiO(s)H2O2e正極2H2O2e→H2(pH2)2OH電極反應(yīng)Ni(s)H2O====NiO(s)H2(pH2)電池符號(hào)Ni(s)NiO(s)|KOH(稀)|H2(pH2)Pt（3）負(fù)極H2(pH2)2OH→2H2O2e正極2H2O2e→2OH?O2(pO2)電池反應(yīng)H2(pH2)?O2(pO2)====H2O(l)電池符號(hào)PtH2(p

3、H2)|NaOH(稀)|O2(pO2)Pt(4)負(fù)極H2(pH2)2OH→2H2O2e正極HgO(s)H2O2e→Hg(l)2OH電池反應(yīng)H2(pH2)HgO(s)====Hg(l)H2O(l)電池符號(hào)PtH2(pH2)|KOH(稀)|HgO(s)Hg(l)3工業(yè)上用鐵屑加入硫酸銅溶液中以置換銅，試設(shè)計(jì)原電池；計(jì)算該反應(yīng)在298.15K時(shí)的平衡常數(shù)，并說(shuō)明此置換反應(yīng)進(jìn)行的完全程度。已知＝0.3402V，＝－0.4402V。（答案：2.4